2[m-(2m+18)+17]=2(m+1)

Solution for 2[m-(2m+18)+17]=2(m+1) equation:

Simplifying
2[m + -1(2m + 18) + 17] = 2(m + 1)

Reorder the terms:
2[m + -1(18 + 2m) + 17] = 2(m + 1)
2[m + (18 * -1 + 2m * -1) + 17] = 2(m + 1)
2[m + (-18 + -2m) + 17] = 2(m + 1)

Reorder the terms:
2[-18 + 17 + m + -2m] = 2(m + 1)

Combine like terms: -18 + 17 = -1
2[-1 + m + -2m] = 2(m + 1)

Combine like terms: m + -2m = -1m
2[-1 + -1m] = 2(m + 1)
[-1 * 2 + -1m * 2] = 2(m + 1)
[-2 + -2m] = 2(m + 1)

Reorder the terms:
-2 + -2m = 2(1 + m)
-2 + -2m = (1 * 2 + m * 2)
-2 + -2m = (2 + 2m)

Solving
-2 + -2m = 2 + 2m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-2m' to each side of the equation.
-2 + -2m + -2m = 2 + 2m + -2m

Combine like terms: -2m + -2m = -4m
-2 + -4m = 2 + 2m + -2m

Combine like terms: 2m + -2m = 0
-2 + -4m = 2 + 0
-2 + -4m = 2

Add '2' to each side of the equation.
-2 + 2 + -4m = 2 + 2

Combine like terms: -2 + 2 = 0
0 + -4m = 2 + 2
-4m = 2 + 2

Combine like terms: 2 + 2 = 4
-4m = 4

Divide each side by '-4'.
m = -1

Simplifying
m = -1